Paper 1 & 2 in JHB south???

[IP4X]

hi there..
Does anyone know where I can get a list of collages in the south of johannesburg where I can do these papers for the wiremans licence??
Or even better if anyone knows of a collage near Alberton??
Also, can anyone tell me how many exams are done a year? Are the papers set nationally or per collage?
Many Thanks..

[Fikani2010]

I have a study guide and an exam generator software to help you with your exams...give me a shout if you need help

[AndyD]

Hi Fikani2010 and welcome to TFSA.

Is the software and study guide you have official or is it something you put together? I haven't come across the exam generator software before.

[Fikani2010]

Paper 1 and Paper 2 Study Guide and Exam Generator

Hello all,
I have compiled a study guide for paper 1 and paper 2 with past exam papers with memorandum. In the study guide, you get more worked out examples on how to answer exam question with great emphasis on calculations which make about 30% of each paper. The exam generator is a software which I have designed to generate exam type questions (10 questions out of 100) in microsoft word-you can generate as much questions as you like just on the press of one button. The reason I came up with this is because I failed dismally before and wasted a lot of money. After much study, i managed to gather past exam papers. I passed my exams with distinction. I guarantee that anyone using my material will pass and if they work a little harder manage even to get distinctions.
For more info please mail me.
Thanks

[Gerrit163]

Fikani, How do we get hold of this guide etc??

Hello all,
I have compiled a study guide for paper 1 and paper 2 with past exam papers with memorandum. In the study guide, you get more worked out examples on how to answer exam question with great emphasis on calculations which make about 30% of each paper. The exam generator is a software which I have designed to generate exam type questions (10 questions out of 100) in microsoft word-you can generate as much questions as you like just on the press of one button. The reason I came up with this is because I failed dismally before and wasted a lot of money. After much study, i managed to gather past exam papers. I passed my exams with distinction. I guarantee that anyone using my material will pass and if they work a little harder manage even to get distinctions.
For more info please mail me.
Thanks

[Fikani2010]

Paper 1 and Paper 2 Study Guide and Exam Generator

Hello,
How To get the study guide and exam generator software? Email me and we will take it from there: fikani2010@hotmail.com

To your success

[AndyD]

Are you selling the guide and the software or are you offering it for free?

[Fikani2010]

Paper 1 and Paper 2 Exam Generator Screenshot

Hello all,
Here is the screenshot of the exam generator. You can get yourself the material to facilitate your study. Please note: The material is not free. I have compiled a study guide for paper 1 and paper 2 with past exam papers with memorandum. In the study guide, you get more worked out examples on how to answer exam question with great emphasis on calculations which make about 30% of each paper. The exam generator is a software which I have designed to generate exam type questions (10 questions out of 100) in microsoft word-you can generate as much questions as you like just on the press of one button. The reason I came up with this is because I failed dismally before and wasted a lot of money. After much study, i managed to gather past exam papers. I passed my exams with distinction. I guarantee that anyone using my material will pass and if they work a little harder manage even to get distinctions. For more info please mail me: fikani2010@hotmail.com
To your success!!
Fikani

[AndyD]

So is the exam paper generator software actually generating questions or is it randomly just throwing up questions contained in a database?

Can you explain how the software is more advantageous that just learning the regs and studying past papers.

[Fikani2010]

Exam Generator

Hello,
The exam generator is designed to be used together with the study guide. You go through the study guide which covers theory and calculations, you also have a chance to look at 8 past exam papers with answers which gives you a feel of how to approach exam questions.Then once you are comfortable, generate one exam print it and set yourself 3hrs to answer the paper without looking at your notes - repeat this as much as you like. Everytime you get different questions, the Exam generator generates questions systematically that means: 99% of the questions generated will be on the actual exam - 99% because I am not the Examiner. That is the advantage of the Exam Generator, it does not however, substitute the need for you to study the regs.

[Fikani2010]

Installation Rules Paper 2 (APRIL 2010 QUESTION 1)

SAMPLE EXAMPLE:
Name FOUR different methods of how the voltage drop of a cable can be determined and give examples for each method.

ANSWER:
EXAMPLE: Suppose a balanced three phase load of 100A is to be supplied using a 35mm2 copper cable over a distance of 100m. Calculate the Voltage Drop (USING FOUR DIFFERENT METHODS).

Let Vd stand for Voltage Drop to be calculated.

We are given: I = 100A and L = 100m (35mm2 of a copper (Cu) cable)
From Table E1 page 307 R = 0.63 Ω/Km for a 35mm2 Cu. NB: We must express resistance in Ohms, to do this use:
R = Value of R in Ω/Km (for a given cable size from page 307 of the Regulation Book) x L (in meters). We also have to convert Km to meters: 1Km = 1000m. Therefore, R in Ohms = Value of R in Ω/1000m x L (in meters)

METHOD 1
Use this formula taken from page 308 of the Regulation Book:
Vd = (Fv x I x R x L) /1000
Where,
Vd is the voltage drop, in volts
Fv is the multiplication factor determined from Table E3 on page 311 of the Regulation Book and Fv = 1 for a balanced three-phase load
I is the current in amperes (100A)
R is the resistance in ohms per kilometer (Ω/Km) from Table E1 and it is 0.63 Ω/Km for a 35mm2 copper cable
L is the length in meters (100m)

Vd = (Fv x I x R x L) /1000
So substituting values we have
Vd = (1 x 100A x 0.63 Ω/Km x 100m)/1000 = 6.30 V

METHOD 2
Use: Vd = I x R
Where,
Vd is the voltage drop, in volts
I is the current in amperes
The value of R in ohms/Km from Table E1 is 0.63 Ω/Km for a 35mm2 copper cable
Now determine R in ohms using:
R = Value of R in Ω/Km (for a given cable size from page 307 of the Regulation Book) x L (in meters). We also have to convert Km to meters: 1Km = 1000m. Therefore, R in Ohms = Value of R in Ω/1000m x L (in meters)
R = (0.63 Ω/1000m) x 100m = 0.063 Ω
Vd = I x R
So substituting values we have
Vd = I x R = 100 A x 0.063 Ω = 6.30 V

METHOD 3
Use this formula Vd = (mV/A/m) x A x m [Volts]
Where,
mV is the unit of voltage in milli-volts. NB 1V = 1000mV
A is the unit of current in amps [100A]
m is the unit of length of the cable in meters [100m]
(mV/A/m) = 1.10 for a 35mm2 copper (Cu) determined from Table 6.3(b) on page 105 or Table 6.4(b) on page 107 of the Regulation Book – The difference between the two tables is that Table 6.3(b) makes provision for a 1mm2 whereas Table 6.4(b) does not. In the exam you will most probably be given Table 6.3(b) [Please familiarize yourself with the use of these Tables and also Table 6.4(a) – Current Carrying Capacity]. NB: From the Tables 6.3(b) or 6.4(b) take the value of z (the impedance) corresponding to the given cable size and not the value of r (resistance) or x (the reactance).
Vd = (mV/A/m) x A x m [Volts]
So substituting values we have
Vd = (mV/A/m) x A x m = 1.10mV/A/m x 100A x 100m = 11000mV = 11V
For phase to neutral Vd = 11V/√3 = 6.35V *[NB: See section 6.2.7 page 120]

METHOD 4
Use Vd = (I x pL)/A
Where,
A is area of cable in this case 35mm2
p = 0.0223, the resistivity of copper conductors
Vd = (I x pL)/A
So substituting values we have
Vd = (I x pL)/A = (100A x 0.0223 x100m) / 35 mm2 = 6.37 V
ADDITIONAL METHODS
In the case of a load with impedance, the voltage drop can be calculated from the following
Vd = (Fv x I x (R cosθ + X cosθ) x L)/1000
The phase angle θ of the load is determined by power factor = cos θ
The reactance X may be obtained from cable manufactures
OR
Voltage drop = (1.72 x I x R) / √3
OR Alternatively the value of the Voltage Drop may be derived from a monogram
END OF SAMPLE EXAMPLE:

APRIL 2010 EXAM QUESTION
QUESTION 1: SANS 10142 PART 1 OF 2008: ANNEXURE E: VOLT DROP (COMPULSORY)
1.1 With reference to FIGURE 1, on the DIAGRAM SHEET (attached), calculate the following:
1.1.1 The total volt drop of the supply (4)
1.1.2 The total resistance of the supply cable (1)
1.1.3 Test the answer in QUESTION 1.1.1 above by making use of any other method. (3)
1.2 By making use of TABLE E1 (attached) only, calculate the actual length of a 10 mm2 copper ECC conductor if the total resistance of the conductor is 0,22 ohm. (2)
[10]

ANSWER TO QUESTION 1 (PRIL 2010 PAPER II:
1.1. With reference to FIGURE 1, on the DIAGRAM SHEET (attached), calculate the following:
1.1.1. The total volt drop of the supply (4 Marks)
Assumption: The installation uses copper cables
NB: We know that the voltage drop shall not exceed 11.5V [5% of 230V] according to the code.
Given:
Point of control (DB): Supply voltage is 230V
The resistive load of 50A is 65m away from the point of control [I=50A, L=65m]
From the Point of control to the cable JOINT we have 40m of 16 mm2 copper cable [R = 1.4 Ω/Km, given this from Table E1]
From the cable JOINT to the load we have 25m of 10 mm2 copper cable [R = 2.2 Ω/Km, given this from Table E1]
Use this formula from page 308 Vd = (Fv x I x R x L) /1000
Where,
Vd is the voltage drop, in volts
Fv is the multiplication factor determined from Table E3 on page 311 we have Fv = 2 for a single-phase load
I is the current in amperes
R is the resistance in ohms per kilometer (Ω/Km) from Table E1
L is the length in meters [40m and 25m lengths of different cables]
Vd = (Fv x I x R x L) /1000
So substituting values we have:
Vd = (2 x 50A x 1.4 x 40m)/1000 + (2 x 50A x 2.2 x 25m)/1000 = 5.6V + 5.5V = 11.10 V

1.1.2 The total resistance of the supply cable (1 Mark)
R = Value of R in Ω/Km (for a given cable size from page 307 of the Regulation Book) x L (in meters). We also have to convert Km to meters: 1Km = 1000m. Therefore, R in Ohms = Value of R in Ω/1000m x L (in meters)
Resistance of a 16 mm2 = 1.4 Ω/Km x 40m = 1.4 Ω/1000m x 40m = 0.056 Ω
Resistance of a 10 mm2 = 2.2 Ω/Km x 25m = 2.2 Ω/1000m x 25m = 0.055 Ω
Total Resistance of the supply cable = Resistance of a 16 mm2 + Resistance of a 10 mm2=0.056 Ω + 0.055 Ω = 0.111 Ω

1.1.3 Test the answer in QUESTION 1.1.1 above by making use of any other method. (3 Marks)
Alternative method 1:
Use: Vd = I x R
Where,
Vd is the voltage drop, in volts
I is the current in amperes [which is 50A]
The value of R in ohms/Km from Table E1 is 1.4 Ω/Km for a 16mm2 and 2.2 Ω/Km for a 10mm2 copper cable
We have already determined R in ohms from the previous question [0.111 Ω]
Vd = I x R
So substituting values we have
Vd = I x R = 50A x 0.111 Ω = 5.55 V
NB: Remember that we have to account for the voltage drop on neutral as well, which is 5.55V in this case.
Therefore, Total Voltage Drop = 5.55V + 5.55V = 11.10V

Alternative method 2:
Use Vd = (I x pL)/A
Where,
A is area of cable [16mm2 and 10mm2]
p = 0.0223, the resistivity of copper conductors
Vd = (I x pL)/A
So substituting values we have
Vd on a 16mm2 cable = (I x pL)/A = (50A x 0.0223 x40m) / 16mm2 = 2.7875V
Vd on a 10mm2 cable = (I x pL)/A = (50A x 0.0223 x25m) / 10mm2 = 2.7875V
Vd of the supply = Vd on a 16mm2 + Vd on a 10mm2 = 2.7875V + 2.7875V = 5.575V
Again remember that we have to account for the voltage drop on neutral as well, which is 5.575V in this case.
Therefore, Total Voltage Drop = 5.575V + 5.575V = 11.15V

Alternative method 3:
*** Use this formula Vd = (mV/A/m) x A x m [Volts]
Determine the mV/A/m either from Table 6.3(b) or 6.4(b)
mV/A/m for a 16mm2 is 2.8
mV/A/m for a 10mm2 is 4.4
Vd = (mV/A/m) x A x m [Volts]
So substituting values we have:
Vd on a 16mm2 cable = mV/A/m x A x m = 2.8 mV/A/m x 50A x 40m = 5600 mV = 5.60V
Vd on a 10mm2 cable = mV/A/m x A x m = 4.4 mV/A/m x 50A x 25m = 5500 mV = 5.50V
Vd of the supply = Vd on a 16mm2 + Vd on a 10mm2 = 5.60V + 5.50V = 11.10V

*** Please note that neither Table 6.3(b) nor Table 6.4(b) was given in the exam, so we would not be able to use this method to substantiate our answer, but it is given here to prove that our answer is indeed right.

1.2. By making use of TABLE E1 (attached) only, calculate the actual length of a 10 mm2 copper ECC conductor if the total resistance of the conductor is 0,22 ohm. (2 Marks)

Recall that resistance in Ohms can also be obtained by using the following method:
R = Value of R in Ω/Km (for a given cable size from page 307 of the Regulation Book) x L (in meters). We also have to convert Km to meters: 1Km = 1000m. Therefore, R in Ohms = Value of R in Ω/1000m x L (in meters)
We are given 0.22 ohms and we have to calculate the actual length of a 10 mm2 ECC, we can apply the above formula:
We are given R = 0.22 ohm
From Table E1, R in Ω/Km is 2.2 for a 10 mm2
The only unknown now is the length (L) of the cable
R = Value of R in Ω/1000m x L (in meters)
So substituting values we have
0.22 ohm = 2.2 ohm/1000m x L
0.22 ohm = 0.00022 ohm/m x L
L = 0.22 ohm / (0.00022 ohm/m)
L = 100m
Therefore, the actual length of a 10 mm2 ECC is 100m for a given resistance value


Refer to figure 4 and calculate the following:
1. Calculate the minimum cable size for the loads.
2. Touch voltage at L3.
3. PSCC at L1
NOTE: Use a three core cable and ignore suppliers transformer and mains supply characteristics.
FIGURE 4
CIRCUIT DIAGRAM NOT ACCORDING TO SCALE

TO GET THE COMPLETE ANSWER TO THE ABOVE QUESTION AND MANY MORE EXAMPLES, ORDER THE COMPLETE STUDY GUIDE AND AN EXAM QUESTIONS GENERATOR SOFTWARE FROM – FIKANI AT: fikani2010@hotmail.com or give me a call at 072 634 8547.
I have Installation Rules Paper1 study guide as well. The study guides consists of a selection of questions and answers similar to the ones you will find on the official exam. All you need to do is use your Regulation Book to answer the questions in each study guide and attempt as many questions as you can that will be generated by the Exam Generator software. Then, once that is done you will be ready to take the exam. Remember, I guarantee that you will pass provided that you follow the instructions correctly! Should you use these study materials and still fail the exams, then send me the original copy of your exam and a copy of your results, I will gladly refund the cost of the study material. However, you are not going to need this guarantee if you follow the instructions as mentioned in the study guide.
Why Use This Study Material?
The study material is a no-nonsense guide for the Installation Rules Paper 1 exam and Installation Rules Paper 2 exam. It focuses on the areas most likely to be on the exam (9 out of 10 Questions generated by the Exam Generator Software will be in the actual exam), plus it provides background information to help you understand some of the more complex concepts and detailed, step by step calculation examples. The focus is on preparing you for the exams and to shorten your preparation time for your exams. The study material offers a self-paced method of preparing yourself for the exams. You do not have to guess what to study; every Module guides you an in depth questions, detailed coverage, and review questions (NO GARBAGE). This step-by-step structure identifies what you need to study, gives you all the facts, and rechecks what you know. If you work very hard, you can pass both papers with distinctions.
GOOD LUCK!

[drdreexx]

hey fikani2010 help me with the study guide and an exam generator software my email
drdreex@vodamail.co.za