Two Phase Installation system???

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  • Smut
    Junior Member
    • May 2012
    • 11

    #1

    [Question] Two Phase Installation system???

    I was just reading through SANS 10142, and under annex P, Authority for issuing a test report and a Certificate of Compliance.
    Which is installation is Two-phase, is it two phases from three phase system?

    Any one to assist
  • AndyD
    Diamond Member

    • Jan 2010
    • 4946

    #2
    Yes, a two-phase system consists of 2 live phases, one neutral and an earth, as you say it's basically a 3-phase system that's missing one phase. It's not very often you see a 2-phase installation nowadays, I've come across only one in the last 15 years or so. Maybe they're more common in certain areas, I'm not sure TBH.
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    • Smut
      Junior Member
      • May 2012
      • 11

      #3
      Thank you very much AndyD,

      Am a bit confused here regarding Voltage drop calculation,

      Click image for larger version

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      E.1.4 Circuit DB/C
      Selected cable voltage drop to be repeated for each load point from the
      previous load point. Amdt 5
      From table 6.4(b) (voltage drop), for a 16 mm2 two-core cable single-phase a.c., the voltage drop is 2,8 mV/A/m

      DB to C1 voltage drop = (2,8 x 10-3) x (5 x 15) x 10 = 2,10 V Amdt 5
      C1 to C2 voltage drop = (2,8 x 10-3) x (4 x 15) x 8 = 1,34 V Amdt 5
      C2 to C3 voltage drop = (2,8 x 10-3) x (3 x 15) x 8 = 1,01 V Amdt 5
      C3 to C4 voltage drop = (2,8 x 10-3) x (2 x 15) x 6 = 0,50 V Amdt 5
      C4 to C5 voltage drop = (2,8 x 10-3) x (1 x 15) x 9 = 0,38 V Amdt 5
      Total voltage drop DB to C5 (red phase) = 5,33 V [1] Amdt 5

      My question is: why should they multiple the current by 5 at C1, by 4 at C2, by 3 at C3, by 2 at C4 and by 1 and C5.

      is this really right?

      My total voltage drop is 1.722V
      Last edited by Dave A; 14-Mar-13, 08:25 PM. Reason: formatted superscript in formula

      Comment

      • Dave A
        Site Caretaker

        • May 2006
        • 22810

        #4
        Originally posted by Smut
        My question is: why should they multiple the current by 5 at C1, by 4 at C2, by 3 at C3, by 2 at C4 and by 1 and C5.
        Point C1 is carrying 5 x 15A draw points, 1 at C1 and another 4 further down the line.
        Similarly C2 is carrying 4 x 15A draw points.

        From a "follow the logic" point of view, it might have been better if they started the point numbering from the furtherest point and worked back towards the supply point for these sorts of schematics. Of course from a signage point of view (if you were actually physically labelling each point) it makes more sense to number from point of supply...
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        • Smut
          Junior Member
          • May 2012
          • 11

          #5
          Thanks Dave,

          I really washed my brain.

          Comment

          • chris541125
            Email problem
            • Dec 2011
            • 6

            #6
            Can the neutral be regarded as a live phase?

            Comment

            • bergie
              Email problem

              • Sep 2010
              • 308

              #7
              it is regarded as a live conductor according to 10142. its not a live phase,otherwise 2 phases and neutral would be 3 phase.

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